I am working on part (c) from the following problem:!
Vbias = 3.3V which should have been given.
Trying to solve for Vout
, I first tried a voltage divider ignoring the diode.
$$3.3V * \frac{1k\Omega}{1k\Omega+2.7k\Omega} = .892V$$
which would mean that the voltage drop across the diode is .892V (?). Which would mean Vout = .892V.
This doesn't seem right to me. In the previous problem (b), I said Vout = .6V which is just Vd and it seems strange to me that adding a resistor in parellel would increase the voltage at Vout node especially if it was smaller, say 100ohm.