# why when calculating rise time we use 2.2 × tau? (RC Low Pass Circuit)

I am just trying to understand why we use 2.2×Tau when calculate the rise time. I can't find a derivation anywhere, I don't understand where this 2.2 came from.

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$$V(t) = V_0(1 - e^{-t/\tau})$$
Lets say rise time 10% to 90% of V0. So in this equation put: $$V(t) = 0.1 \cdot V_0$$ and find $t_1$. Similarly put: $$V(t) = 0.9 \cdot V_0$$ and find $t_2$. You'll get: $$rise time = t_2-t_1 = 2.2 \tau$$