So I solved this using current division and KVL to find Vs, but I am posting because I wonder if there is a more simple way to find Vs in this circuit.
(This is a textbook example, not homework; the given answer is Vs = 9V).
Will someone verify my procedure and let me know if there is a better way to do this problem?
Labels: R1 = 20k ohm resistor, R2 = 60k ohm resistor, R3 = 120k ohm resistor
Step 1: Using current division, I_R2 = 0.1mA = (120k/180k)*I_R1 The unknown here is I_R1. So, that gives I_R1 = 0.0001 A * (3/2) = 0.00015A. Step 2: V_R1 = 0.00015A * 20k ohms = 3V Step 3: V_R2 = 0.0001A * 60k = 6V Step 4: Setup KVL around the left loop: -Vs + 3V + 6V = 0 Step 5: Isolate Vs and simplify the KVL equation: Vs = 9V
So, that's correct, but, did I get the answer correct by chance, or did I find the correct procedure? Also, what could I have done to simplify the process?