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Could someone tell me if I've used the right approach for this problem?

Assuming IDEAL DIODES:

enter image description here

I am aware this is not a practical application and that it would not work in real life, but I just to follow the right process in analyzing the circuit theoretically.

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1 Answer 1

up vote 2 down vote accepted

Since the 10V battery and the diodes D1 and D2 are connected such that both the diodes are forward biased all the time. So this output of this circuit has got no relation with the input of the circuit.

schematic

simulate this circuit – Schematic created using CircuitLab

As far as output is concerned, the voltage across a short-circuited battery is the output here. Since the diodes are ideal, the battery 'burns out' and output becomes zero volts, in case of non-ideal battery. Talking about ideal case, you can not short circuit an ideal voltage.

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Thanks so much :) –  user2802349 Jun 16 at 7:28
    
@nidhin: I have trouble understanding your answer: in the first case, D1 seems to be reverse-biased at first glance, but if the resulting Vo is 0V, then D1 is forward-biased; this seems to be a contradiction. The same applies to the second case and D2. After all, D1 and D2 seem to be short-circuiting the 10V supply. I assume you are right after all, but where is the flaw in my logic? –  user36113 Jun 16 at 8:35
    
@fmunkert yes you are correct... I didn't notice that.. I will correct it. –  nidhin Jun 16 at 8:45
    
@fmunkert thanks for pointing out the error. Since I can not delete an accepted answer, I have edited the answer. –  nidhin Jun 16 at 9:21
    
@user2802349 I have changed my answer completely. Please go through it. –  nidhin Jun 16 at 9:24

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