# Compute for resistance (Resistance circuit)

Hi how do you solve this problem? I am confused.

simulate this circuit – Schematic created using CircuitLab

Find $R_{AB}$, $R_{CD}$, $R_{EF}$, $R_{AE}$

I came up with this: $R_{A-B}$ = 1 $\Omega$ , $R_{C-D}$ = 4 $\Omega$ , $R_{E-F}$ = 7 $\Omega$ , $R_{A-E}$ = 2 + 5 = 7 $\Omega$

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+1 for posting a schematic with your question, even if the first version was rudimentary. Most questions come without one and that makes them a lot harder to answer. – Ricardo Aug 1 '14 at 23:57

Have you covered equivalent resistances? Essentially, it is a way to combine resistors in series or parallel until you get a single resistance, working your way from out to in.

Let's say you want to find $R_{AB}$.

First, your have a series combination $R_5$, $R_6$, and $R_7$. $$R_{5,6,7} = R_5 + R_6 + R_7 = 18 \Omega$$

simulate this circuit – Schematic created using CircuitLab

Now you have a parallel combination between $R_4$ and $R_{5,6,7}$. $$R_{4,5,6,7} = \frac{R_4 \cdot R_{5,6,7}}{R_4 + R_{5,6,7}} = 3.27 \Omega$$

simulate this circuit

You are almost done! Now, since you are looking for the equivalent resistance between A and B, you have a series combination for $R_2$, $R_3$ and $R_{4,5,6,7}$: $$R_{2,3,4,5,6,7} = R_2 + R_3 + R_{4,5,6,7} = 8.27 \Omega$$

simulate this circuit

Last Step!

You have a parallel combination between $R_1$ and $R_{2,3,4,5,6,7}$: $$R_{AB} = \frac{R_1 \cdot R_{2,3,4,5,6,7}}{R_1 + R_{2,3,4,5,6,7}} = 0.892\Omega$$

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you saved me so much time, have my upvote! I'm just editing your answer to include some nice formatting, have a look at it after to learn how to use mathjax. – Vladimir Cravero Aug 1 '14 at 18:36
This is what I need! Thanks! – Brian Sanchez Aug 1 '14 at 18:43
Ahh, thank you. I was trying to figure out how to clean the equations up. Thanks for the edit! And you're welcome. – Ornusashas Aug 1 '14 at 18:46
@Ornusashas to understand how to write great answers just check out some of the frequent ones. That's what I did at least... You might also learn some electronics (not sure if you need to...) – Vladimir Cravero Aug 1 '14 at 21:27

$$R_{ab} = (((5 + 7 + 6) || 4) + 2 + 3) || 1$$

Combine the resistors in series and parallel until you end up with a single resistance between the two nodes and you have your answer.

I believe for $R_{ae}$ one would need to employ a wye-delta transform.

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