Tell me more ×
Electrical Engineering Stack Exchange is a question and answer site for electronics and electrical engineering professionals, students, and enthusiasts. It's 100% free, no registration required.
up vote 4 down vote favorite
2

In one of the answers to this question, it is stated that wiring one of the coils on a bipolar stepper backwards can cause the motor to step improperly, or not at all. I've salvaged several steppers from discarded electronics (printers, scanners, typewriters), and I'm curious, is there a better method than trial and error for determining the proper polarity of the coils?

If I reverse both coils, does the motor simply run in reverse?

share|improve this question
it's probably too much to hope that those leads are color coded to any kind of standard. – JustJeff May 10 '11 at 20:46
@JustJeff - They're usually color coded, but the color-code is different for almost every motor, and you don't know how it maps to the coils. – Connor Wolf May 10 '11 at 21:43
@Fake Name - that's what i'm saying. if you pulled the same motor from the same model of three printers, i imagine the phases would have the same colors. but two different motors? wouldn't count on it. – JustJeff May 10 '11 at 21:45
@JustJeff - Whoops, I somehow completely glossed over the "Any kind of standard" part of your comment. Too early in the morning for me, I guess. – Connor Wolf May 10 '11 at 22:34

2 Answers

up vote 2 down vote accepted

If you think of the phases of the stepper, it would go from [--] to [-+] to [++] to [+-], and then repeat.

If we label those phases as: [--] J [-+] K [++] L [+-] M

Then you go "forward" by stepping JKLMJLKMJLKM... and "backwards" by stepping MKLJMKLJMKLJ...

If you flip the bit on both, we now have: [++] J' [+-] K' [--] L' [-+] M'

So when you drive, you get J'K'L'M'J'K'L'M'... But J' is really L, K' is really M, L' is really J and M' is really K on the motor, so you are moving LMJKLMJKLMJK... which is the same sequence of the "forward" stepping, but with the cycle starting half-way in the middle of the original cycle.

So, yes, if you reversed the polarity on BOTH coil sets, you would still move in the same direction. However, you will be off by half a stepper revolution. Depending on the gearing, the difference would probably not make a difference.

EDIT

I updated to indicate polarity as +/- (versus 1/0 in my original posting).

This is easier to visualize graphically -- if you treat each winding 1 as the X coordinate, and winding 2 as the Y coordinate, then you are stepping between four quadrants. If you then half- or quarter- step, you are just increasing the number of points that define your loop. Taken to the limit, if you have the X=sin(wt) and Y=cos(wt), you'll have a smooth circle; and if you reverse the sign of one (say X=-sin(wt)), you'll just go through the circle in reverse direction.

share|improve this answer
1  
Perfect, thank you. Indeed, it looks like swapping the polarity on one of the coils will send you in reverse and off by one or two steps, depending on which coil was reversed. I wonder what happens when you're half/eighth/sixteenth stepping... – Mark May 11 '11 at 17:35
up vote 2 down vote

(this extra information doesn't really answer your question directly - but 'add comment' has broken on my browser since the last big UI change)

Here's a trick - if you have a stepper with random colored wires you can easily find the pairs of wires that correspond to each wire - turn the stepper manually, feel how easily it moves, choose any wire, short it to other wires until you find one which makes the stepper harder to turn by hand - those two are wired to the same coil

share|improve this answer
1  
I understand how to determine which wires belong to the same coil (easiest way is to measure resistance), I would like to know what happens if one of the coil is wired backwards. – Mark May 11 '11 at 17:31

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.