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In an answer to this question Leon Heller links to a tutorial which includes the following graph:
enter image description here
I'm a bit confused. Shouldn't the graph for an RC filter monotonously decrease, without the inflection point?

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up vote 10 down vote accepted

The graph is correct. The curve looks a bit unusual because the voltage scale is linear. The Bode plot will have a slope of 6dB/octave which will be a straight line on a logarithmic graph. But a straight line on a logarithmic graph is a hyperbola on a semi-logarithmic graph.
If the curve were to approach a decreasing asymptote the voltage would eventually become negative. Not something you get from a divider.

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Oops, I missed that. Thank you. –  Federico Russo May 30 '11 at 7:49
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