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I have simulated the LM723 based regulator circuit in LTSpice

enter image description here

And after running it I got 16A currents (blue/green) on diodes in rectifier. The max current I supposed to get here was 3.3A. Please tell me what is wrong? I have tried to use different MUR860 models and it did not helped.


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Try decreasing that freakishly large C5 to something smaller. – Dejvid_no1 Feb 18 at 19:43
6800uF - 12A; 4700uF - 9A (but ripples appear) – Roman Feb 18 at 19:58
+1 for not blindly accepting the current peaks but asking yourself: What is going on here ? – FakeMoustache Feb 18 at 20:03
up vote 3 down vote accepted

There are a few problems with this schematic

1) You are using an ideal voltage source, You may want to add some inductance and resistance to simulate wires. Mains power is not infinite, and neither is the current from a transformer. Your transformer is going to have a lag on power that it can deliver, you should probably simulate this. Another thing to watch out for is transformer saturation. (unless your not getting power from AC mains)

2) As the other answers say, you have a huge capacitor, is throwing more capacitance at the problem going to be a good solution? If the current is too high, then you need to change the design, not the parameters of the design. At these current levels you should probably use a DC to DC instead of a vreg unless price is an important consideration. You are going to burn up lots of power. Its better to put smaller amounts of current at a higher voltage through the rectifier You can get cheap DC to DC regulators that are 780X drop in compatible that will handle 1 amp, you can parallel them if you need more current. If that doesn't work then go find a DC to DC IC. Have you considered a AC to DC power supply such as a "wall wart"? People make these things for less than 20$.

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Add some series resistance to that 10mF capacitor.

Add some series resistance to the voltage source. In the real world that voltage source will be a transformer and it's secondary winding will have some series resistance.

I'm assuming you're using proper models for the diodes so they should already have some series resistance.

Think about what will limit that current in the real world: the series resistances of all the components through which that current flows. In a simulator it is easy to get 10 kA of current, in the real world it is not that easy.

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Is there any way to easy calculation of cap ESR having it's dissipation factor? I have found the method here but afraid that it is too complicated for my level of knowledge ))). But may be there is a constant or average value to use? – Roman Feb 18 at 20:27
Instead of calculating, why not try to find a datasheet of such a capacitor and see if the manufacturer lists the ESR ? Some manufacturers are: Panasonic, Nichicon, Nippon Chemicon, Vishay or search on digikey or Farnell, Farnell usually also has the datasheet. – FakeMoustache Feb 18 at 20:31
The data sheet of my Rubycon MXC series does not have the ESR value. – Roman Feb 18 at 20:33

It looks like you're trying to provide about 15 V to a 6 ohm load. Unless I misunderstand your schematic... So that's 2.5 A.

Now consider that the diodes only turn on and pull current from the AC source about 1/5 of the time (only when the 23 V sin goes above the 20 V or whatever rectified voltage you're getting).

In order to average 2.5 A (plus whatever is sloshed in the the parallel caps) at 20% duty, you'll need to average about 12.5 A during that 20% of the time. So, a max of 16 A doesn't seem unreasonable to me.

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