I am in the learning curve on LED lighting. I bought a 12v RGB LED controller that has a common anode with three color grounds that are rated to 2A on each channel. I have a number of 3W RGB LED’s with a heatsink, but no matter which resistor’s I use they cook and burn up. Even the 1W resistors cook. Granted I am testing with just 1 of the LED’s, but what am I doing wrong? Is 2A just too much for one LED? I am building a lamp with 16 of the LED’s but I should be able to test the controller with one LED? Thanks for your help.
closed as not a real question by The Photon, Dave Tweed♦, Olin Lathrop, Nick Alexeev♦, Kaz Dec 17 '12 at 16:43
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I'm not an expert but I'm pretty confident that I can answer these questions without further information. If the controller is like mine, and gives 12 volts regardless of the load, then he's asking the resistor to drop about 9 volts (+/- 1 volt) - at 350 mA, that's 1.1 watts. In any case, no 3 watt RGB LED is going to want 2A? The 3 watt RGB LEDs I use are rated at 350 mA per colour. My advice is to use a multimeter to determine the voltage drop across the components and the current flowing through them.