I am in the learning curve on LED lighting. I bought a 12v RGB LED controller that has a common anode with three color grounds that are rated to 2A on each channel. I have a number of 3W RGB LED’s with a heatsink, but no matter which resistor’s I use they cook and burn up. Even the 1W resistors cook. Granted I am testing with just 1 of the LED’s, but what am I doing wrong? Is 2A just too much for one LED? I am building a lamp with 16 of the LED’s but I should be able to test the controller with one LED? Thanks for your help.
closed as not a real question by The Photon, Dave Tweed, Olin Lathrop, Nick Alexeev, Kaz Dec 17 '12 at 16:43
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, see the FAQ.
I'm not an expert but I'm pretty confident that I can answer these questions without further information. If the controller is like mine, and gives 12 volts regardless of the load, then he's asking the resistor to drop about 9 volts (+/- 1 volt) - at 350 mA, that's 1.1 watts. In any case, no 3 watt RGB LED is going to want 2A? The 3 watt RGB LEDs I use are rated at 350 mA per colour. My advice is to use a multimeter to determine the voltage drop across the components and the current flowing through them.