# Math: Temperature tranform equation [closed]

While reading the MAX6605 datasheet, which is an analog temperature sensor, I ran across the following:

The temperature-to-voltage transfer function has an approximately linear positive slope and can be described by the equation:

VOUT = 744mV + (T ✕ 11.9mV/°C)

where T is the MAX6605’s die temperature in °C. Therefore:

T (°C) = (VOUT - 744mV) / 11.9mV/°C

To account for the small amount of curvature in the transfer function, use the equation below to obtain a more accurate temperature reading:

VOUT = 0.744V + 0.0119V/°C ✕ T(°C) + 1.604 ✕ 10^-6 V/°C^2 ✕ (T(°C))^2

My algebra is terrible. How do I solve for T(°C) from the last equation?

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## closed as off topic by The Photon, Brian Carlton, Nick Alexeev♦, W5VO♦Nov 15 '12 at 4:47

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Use the quadratic formula. See en.wikipedia.org/wiki/Quadratic_equation – The Photon Nov 14 '12 at 22:24
You can use WolframAlpha to solve for you or to check your answer. – Samuel Nov 14 '12 at 22:48

 1.604X10^-6T^2 + 0.0119T + (0.744 - VOUT) = 0