Bit of a strange question, but what is it? My physics teacher said it was kind of like a "push" that pushes electrons around the circuit. Can I have a more complex explanation? Any help is much appreciated.
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Your teacher was right. Current is electric charges (usually electrons) moving. They don't do that by themselves for no reason, no more so than a shopping cart moves across the floor of a store by itself. In physics, we call the force that pushes charges the electromotive force, or "EMF". It is almost always expressed in units of volts, so we usually take little shortcut and say "voltage" most of the time. Technically EMF is the physical quantity and volts is one unit it can be quantified in. EMF can be generated several ways:
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Using a fluid analogy, Voltage is pressure, Current is Flow rate. |
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A voltage appears whenever there is an imbalance of electrical charge (i.e. electrons). Since like charges repel and equal charges attract, any collection of electrically charged particles creates some kind of force on each other. If there is an imbalance of negative to positive, a kind of "pressure" or "push" is formed. In conducting materials, electrons are free to flow through the material, as opposed to being fixed in atoms, and will therefore flow to the point of least "pressure". Some complicating considerations:
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Actually we can't. Electrostatic force is proportional to the potential gradient but not directly to potential. Force on a one coloumb of charge is proportional to the potential gradient. \$ F= Q \times {d[V]\over dl } \$ Actually ,1V mens if you 1Joule of electrical energy will be transfered into mechanical energy on a +1coloumb charge [so it will accelerate , or increase it's 1/2mV^2 by 1J ]. It's actually analogous to energy, But anyway this answer will confuse a newbie. |
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Adding to what Gunnish said: Voltage at point A is literally a measurement of the work you would expend if you were to push a positive charge from 0V (usually either defined as infinitely far from A, or ground) to A. Voltage is important in electronics because if we start with a positive charge at point A, it is able to DO that same amount of work getting to 0V (ex. turning on an LED in the process). |
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A definition I've heard is:
In other words, voltage is the energy given to a unit of charge, i.e., \$ V = {dE \over dQ} \$, where \$ E \$ is energy and \$ Q \$ is charge. |
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What is pushing the elections is a difference in potential energy, much like the way you are being pushed/pulled to the earth by gravity. This generates a favorable probably for the electrons to move one way over another, this also partly explains why the electrons move "randomly" in a wire. |
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"Voltage" is a derived quantity. It is hard to understand its Physical meaning without understanding the quantities it is derived from. It all starts with the force between two point charges. Let the charges of the points \$ P_1 \$ and \$ P_2 \$ be \$ q_1 \$ and \$ q_2 \$. Let the distance between them be \$ r \$. The fundamental theorem says that, the force between these two charges are proportional with the amount of charges, and inversely proportional with square of the distance between the charges. That is: \$ F = k\frac{q_1 q_2 }{r^2} \$ Let the location and the charge of \$ P_1 \$ be fixed. Now the force depends on the location and charge of \$ P_2 \$. So we define a vector field called "Electrostatic Field". Direction of the vector field is the same with direction of the field of the force between \$ P_1 \$ and \$ P_2 \$ when \$ q_2 \$ is positive unit charge. And magnitude of the field is the force per charge \$ q_1 \$ when \$ q_2 \$ is unit positive charge. That is: \$ \bar{E} = \lim \limits_{q_1 \to 0} \frac{\bar{F}}{q_1} \quad \mbox{(} q_2 \mbox{ is unit positive charge)} \$ We make \$ q_1 \$ approach to zero in order to neglect some other electromagnetic effects disappear; don't let it confuse you so much. Now we come to see that these quantities we defined are very similar to some other Physical quantities we know. For example, the force above is very similar to the force between the Earth and an space object like the Moon. And the \$ \bar{E} \$ field is very similar to the gravitational field of the Earth. Then the idea of defining electrical potential arises which is similar to the potential of a space object with respect to the Earth. Potential of a point in the space around Earth is energy per unit mass to bring an object (which has unit mass) from infinity to that point. When we define it in Electrostatics, the potential of the point \$ P_2 \$ becomes: \$ V_2 = - \int \limits_{\infty}^{P_2} \bar{E} d\bar{\ell} \$ Then the potential difference between two independent points (\$ P_2 \$ and \$ P_3 \$) in the space within the \$ \bar{E} \$ field (caused by \$ q_1 \$) is: \$ V_2 - V_3 = \left(-\int \limits_{\infty}^{P_2} \bar{E} d\bar{\ell}\right) - \left(-\int \limits_{\infty}^{P_3} \bar{E} d\bar{\ell}\right) = \int \limits_{P_3}^{P_2} \bar{E} d\bar{\ell}\$ Note that electric field is curl-free, which means it can always be represented as gradient of a scalar field (\$ \bar{E} = - \bar{\nabla} V \$). The these line integrals are independent of path. So, this is the true definition of the potential field. A point will always have a potential even if there is no charge on it. Thing it as of "the energy needed to bring a unit charge to there from infinity". Potential difference between two points is similar; it is the energy needed to carry a unit charge from one point to another. Or think it on a more concrete example like for celestial bodies. Potential difference between 100km height and 200km height above Earth's surface is nothing but differences of potential energies between two 1kg objects at the given heights. When we come to real world, potential of a point is some of all individual potentials caused by the charges around (theory of superposition applies). |
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The quickie, 1st approximation, rule-of-thumb answer: voltage is electrical pressure. But expanding on that: Voltage is not like pressure, not exactly. Instead it's a physics concept called "Potential." It's more like altitude in a gravity field, where each electron or proton is like a boulder. If a boulder is at the top of a hill, it's at a high-Potential location, this means the boulder is storing PE, and will release this energy as KE if it's allowed to move downhill (move to a low-Potential location.) More precise: voltage is electric Potential. It is not force (it's not like the weight of the boulder or like the Newtons of force upon an electric charge in an e-field.) Also it's not potential energy, since gravity, altitude, and Potential still exists even when the boulder is not present. Potentials are part of the field itself. Voltage is a way of describing/visualizing/measuring electric fields. We can draw flux-lines between opposite electric charges. Or instead we can draw the pattern of voltage, the iso-potential surfaces, perpendicular to the flux lines. What is voltage? It's a pattern of concentric onion-layers which surround any charged object, with the onion-layers running perpendicular to the flux-lines of the electric field. So, voltage is one way of describing an e-field. Flux lines are the other more common way. |
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protected by Olin Lathrop Dec 31 '12 at 17:47
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