I'm breaking my head over this. I've got 1200 samples of true RMS current using a BK Precision 5492B over a period of 10 minutes (this means a sample every 0.5 seconds). I'm using a power factor of .8 for this calculation.
P (apparent) = Irms x Vrms
P (real) = P (apparent) x Power Factor.
If I sum all of my 1200 samples of P (real) I get 0.8523W
Now, since I took samples every 0.5 seconds, that means in 1 hour there are 7200 samples, so if I divide that number by 7200 I get: 0.000118385kWh
Am I correct in my calculation?
I'm trying to figure out the cost of running this device for 1 hour.