In the picture below we see 3 LEDS in a parallel circuit. When the switch is closed only LED 2 and LED 3 are on. LED 1 isn't on because it's a diode in the opposite direction. You observe what happens when the switch is closed and opened by opening the switch first and then closing it. Explain:
- Which LED(S) are on for a short while after opening the switch;
- Which LED(S) are not on for a short while after closing the switch.
p.s. - I probably made some mistakes in translation. Here is the image of the circuit:
I can't answer any of these questions. I know for sure they have something to do with electromagnetic induction. But I'm having trouble grasping what will happen in these situations. Can someone help? I know that if a switch is open and closed there will be induction for a short time.