When Engineers talk they want you to know that they are very smart and have their own language just to prove it... Kinda just like "COP TALK" ie: "the perp exited the vehicle and entered the establishment at which time he secured the purchase of a coca-cola product just prior to re-entering his vehicle ...."
For electrical or electronic purposes:
"Drawing" means consuming, pulling or using some resourse....Just as you may "DRAW" the milk up the straw from your cup, which is the source, in electronics you can "DRAW" more current from the source. Used almost exclusively in the term "Drawing Current"
"Current" is a term we use to visualize/represent/measure electricity running through a wire.
When people say a device is "drawing current" they simply mean that the device is pulling or using power from the power supply. In electronics we are always obsessively worried about how much juice our devices are requiring or currently using. Maybe we are worried because we are using a battery and we are worried we may kill the battery if we "DRAW TOO MUCH CURRENT" Or perhaps we may have a problem with a device. Maybe it doesnt turn, or light up, or make the correct sounds.... BUT!!, it does seem to be "Drawing a lot of current" Thats valuable information to the troubleshooter and it sure does make you sound smart to people that dont know what you are talking about.
A "LOAD" is simply a device, or part of a circuit that is using power from some electrical source. When looking at an electrical circuit that operates something such as a washing machine, air conditioner or hard drive in a computer, we say that component represents or is in fact "THE LOAD" of the circuit.
BUT!!!!! The amount of LOAD can change depending on what the device is doing at any specific time.
Alternatively, the "LOAD" may also be referring to the total amount of power that is being pulled from the power source. So, we may also say, "The air conditioner is putting a heavy LOAD on our circuit or collectively the air conditioner, washing machine and the computer is too much LOAD for a single household circuit.
When a device is under load that means it is doing work and it needs more power from the power source or, "Power Supply". You may/will see the term, "It is under heavy load" Obviously, HEAVY LOAD gives the idea that the device is working very hard, perhaps near its maximum capability. A light load assumes the opposite and also obvious.
So the correct question is not really why does a device under load draw more power, it is really more of an understanding of what the term load actually means in this complex Engineers vocabulary. The fact that a device is "Under load" actually directly means that the device is simply using power or current from the supply. So, for any specific circuit, the heavier the Load becomes, the more current or power will be taken or drawn from the power supply. A circuit that is NOT under load is not drawing any power or current at all.
Please note that "Power" and "Current" have been used in my explanation just as a generic way to describe electrical energy being used by a device or circuit. Technically, "Current" and "Power" although they are both directly related, are 2 different measurements and have 2 different values for any given circuit.
I hope this helps and hits the heart of your question..
Thanks for reading,
SORRY! I only saw the top portion of your question about drawing currents and loads... Throwing in the motor thing shows me that you have a higher level of understanding than I was actually writing for.
Now the motor thing does throw in a bit of a monkey wrench into things simply because of the incredibly interesting things that actually go on when a motor is running.
It seems pretty obvious that any device that has a heavier load will require more power to operate. For example a motor that is currently lifting 10 lbs should pretty much draw double the power when the weight changes to 20lbs. Not exactly though, due to many reasons like friction and other factors, but suffice to say that logic would dictate that a machine that does double the amt of work should use double the energy (everything else being equal). So in a way, "LOAD" may be fairly described as the amount of work a machine is doing. So, the heavier the lifting in our example, the heavier the LOAD, the more power is required. Pretty straight forward.
So looking at the motor thing strictly as a DC Ohms law thing, and considering your level of understanding, there should not be any question why a heavier load will increase the current in a circuit. . When the load gets greater, effectively the resistance of the load decreases. So if the applied voltage stays the same but the load resistance goes down, obviously the current must go up. Simple ohms law. Only problem is, the numbers dont work.
Looking at this from a straight Resistance, Voltage, Current relationship, the motor thing doesnt seem to make electronic sense. The numbers dont calculate out the way you thought. And this is the exact reason that I chose not to pick AC theory or communications as my major field of study. When you get into these theories, things start to appear to break the old OHMS law thing. Notice I said appears. When you finally sit down and do 4 pages of mathmatical equations, all based directly on and in accordance with ohms law, it all works out and proves out to be exactly what they said should happen even though it doesnt seem to make sense at first glance..
What is actually going on in a motor when it is running is a complex series of interracting events that are all affecting the current flow in their own way. Along with friction, heating of the windings, and some other minor things taking place, there is something called counter EMF. This is the most influential factor believe it or not.
When you are running an electric motor(lets please just stick with a dc motor for our purposes. My brain is already starting to hurt just thinking of trying to explain the AC motor.), theoretically the only power that is consumed is the loss in the friction of the bearings and the coil windings. Otherwise an electric motor would "theorectically" draw no power. Because of the design of the electric motor, it actually generates its own electricity. .......in a way....... Just as a transformer or electric generator work
, the electric motor also employs the idea that a charging coil of wires will actually contain energy in the magnetic field that surrounds itself when a electric current is passed through it. When this field collapses, it induces a voltage on the surrounding coil of wires 100% equal and opposite of the current that was used to charge the coil initially. (minus the losses in the coil.) This is called the counter EMF. In a Transformer or generator device, the resulting electrical current produced is sent to its load or power supply to be used as needed. But in the electric motor, this reverse current flows back into its own power supply having the effect of seemingly replacing the current that was originally pulled from it. Now add in the heating of the wires, the effect of the permanant magnets that are also part of the DC motor, and other factors and for me at least, it becomes mathmatically imposible to calculate.... Well, not really, but...Get a Watt meter and measure the actual power. Much easier..Do the math one time in your life to prove out the theory but after that just trust the Watt meter. If you attempt too many of these type calculations in your life time your head will explode so please use extreme caution.
One thing missing from the above explanation is that although we were talking about a dc motor we are still dealing with an alternating current building and collapsing on a coil because as a DC motor rotates, it is constantly reversing the polarity of the charge in the coil wires effectively producing an AC voltage. This could probably take a lot bigger and better explanation but i got to cut it off somewhere.
Ok, so now to explain why the current increases when the motor is held back or even stopped while full power is still applied. Now that the motor is stopped lets say, the magnetic field around the coil never collapses. Without the motor turning you are simply running full voltage directly into a straight piece of wire. A long coiled wire perhaps, but still not much electrical resistance. So without the on and off switching from the rotation of the motor, the full voltage from the power supply is constantly applied to the motor coil. Then the coil starts to pull massive amounts of current from the supply and at the same time heating up the coil wires trying to expell this basically shorted energy. Hence! Current goes through the roof and you most likely destroy the coil windings. It is easy to look at it on the surface and say, since the motor is not turning it must be drawing less current/power... But as I hope I have explained, thats not really how it works.....
Once again I hope my explanation has helped..