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Short channel effects arise when the channel length (the distance between the source and drain of a mosfet), is of a similar order of magnitude to the depletion layer (the area between a p type and n type material that has no charge carriers). This causes it to behave differently to long channel devices. One of the main differences is that short channel ...


1

Take a look at the example circuit here. To get an approximation of the voltage offset error at the output, look at the two equations for error due to Ib+ and Ib- (I'm on a tablet right now so I won't repeat them here.) Add the values in your datasheet for max input bias current and input offset current and plug them into each equation, and find the larger ...


3

It will matter only if you have a connection that uses the "ground" at 0V in a +/-12V system. If you have only connections that use the +/-12V rails but never touch the 0V ground then yes you can a 0 to 24V power supply. Obviously, if you have a line that uses 0V in a +/-12V system you could substitute that with a 12V line in a 0-24V system. As you said, ...


1

In your second line, Vdd and Vctr are 6 volts. That means the switch is on, not off. 100 ohms is the standard on resistance. The first line, with Vdd and Vctr at 0, gives the off resistance. Dave Tweed is right - you need a pull-down resistor on pin 13. Depending on the LEDs you're using, you may be violating the switch's ratings. If the Vf of the LEDs is ...


2

My databooks show an off-state leakage current of ±50 nA (max @ 25°C, typically ±0.1 nA) for both the 4016 and the 4066. With a Vcc of 6V, you could model this as a resistance of approximately 108 Ω. I don't know why the model you found has such a low value.


3

CMOS devices normally have a high input impedance. For the 74xx and similar logic series this information is often provided in a family guide instead of being repeated in each datasheet. For example the Philips 74HC/HCT/HCU family guide shows on page 6 the following that indicates a maximum input current of 1uA for the 74HCXXX series: So while your wire ...


0

When you apply a voltage to the gate of an NMOS FET that is greater than the threshold voltage \$V_{t}\$, a channel of electrons is formed under the gate. That channel connects the drain and source so that when you apply a voltage \$ V_{ds}\$, a current flows from between these terminals. In this mode, the MOSFET behaves almost like a resistor, so the ...



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