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| visits | member for | 1 year, 1 month |
| seen | Jan 24 at 20:04 | |
| stats | profile views | 19 |
Future electronic engineer, data fanatic, interested in computer vision, photography, web applications, low-level C & assembly hacking, microcontrollers, brazilian guitar and has recently been introduced to the benefits of a good ChimarrĂ£o while thinking.
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Mar 24 |
awarded | Yearling |
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Apr 11 |
answered | How to determine a system is stable using pole zero analysis? |
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Apr 10 |
comment |
How to make cards for POS? sd cards won't fit your needs? they're small (the micro ones), cheap, and they're easy to interface |
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Apr 9 |
revised |
What do you call the dynamic range of a variable gain amp? deleted 2271 characters in body |
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Apr 9 |
awarded | Editor |
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Apr 9 |
revised |
S = VI*/2 derivation added 4122 characters in body |
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Apr 9 |
comment |
S = VI*/2 derivation I'll edit my answer to show what's the physical interpretation of Q ;). That's a topic that's not well covered in some circuit analysis books, it's worth mentioning |
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Apr 9 |
comment |
S = VI*/2 derivation almost that, the amount of I in the direction of V multiplied by V is the real power P, the amount of I perpendicular to V multiplied by V is the REACTIVE power Q, P+jQ is the complex power, or apparent power ;) |
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Apr 9 |
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What do you call the dynamic range of a variable gain amp? read the questions: he's actually after the real definition of dynamic range. if you try to define it in every possible context, you'll run out of time and words |
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Apr 9 |
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S = VI*/2 derivation Yep. you're right, that's NOT Q. The reactive power is defined only in terms of the phase difference between voltage and tension, and it's a value that's directly related to the definition of S as a phasor. It's the power that would be delivered by the current in quadrature with the voltage. The time varying component is not taken into account, because in this sense what really matters is the mean power at the load. The varying part EXISTS, is really there (watch a incandescent light bulb, for example), but, over time, the power is related only to the static part of s(t). ;) |
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Apr 9 |
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What do you call the dynamic range of a variable gain amp? The problem is that he defines it as having to be calculated at maximum and minimum gain, and that just makes sense in one very specific context. That's the case of a sensor, but not the general case, and definitely, for me, not a "definition" per se |
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Apr 8 |
answered | What do you call the dynamic range of a variable gain amp? |
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Apr 8 |
awarded | Teacher |
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Apr 8 |
answered | S = VI*/2 derivation |
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Apr 8 |
awarded | Supporter |