I am modeling a simple transimpedance amplifier with a current source input and some extra components for the photodiode model. For my AC plot the Y-axis says dB, not dbv (or dbV) so what am I referencing? I'm not sure how that works here (current source input, plus some negative bias on the opposite side). In the meantime I switched to absolute values and mentally compensate for what seems like a 1000x value of the real value. thanks
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1\$\begingroup\$ You might get better answers by adding a screenshot \$\endgroup\$– ChristianMay 24, 2017 at 19:31
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2\$\begingroup\$ electronics.stackexchange.com/questions/212779/… \$\endgroup\$– jonkMay 24, 2017 at 19:52
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1\$\begingroup\$ IIRC, it's dBV (for a voltage probe). If you want to check, just add a 1 V AC source to your design, ground one pin, and put a probe on the other one. \$\endgroup\$– The PhotonMay 24, 2017 at 20:36
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\$\begingroup\$ It's dBW, dBV or dBI, depending on whether you're measuring power, voltage, or current. What is your problem? \$\endgroup\$– Bruce AbbottMay 26, 2017 at 8:44
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\$\begingroup\$ thank you all, you've been very helpful. it's amazing how much this program can do that is not documented very well, or at all. \$\endgroup\$– Matthew CarsonMay 27, 2017 at 17:56
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Remember dB is a ratio, in this case vin to vout if you divide V/V you get a unitless value which dB is. You can always change the axis to linear, log or whatever you want if you need further clarification by right clicking on the axis and selecting a different mode.