7 Adding images
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I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

enter image description here

BJT Class A Circuitschematic1![][1]

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

DC Load Line Schematic

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

enter image description here

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

schematic1![][1]

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

DC Load Line Schematic

6 Adding images
source | link

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

enter image description here

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

enter image description here

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

enter image description here

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

enter image description here

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

5 added 83 characters in body
source | link

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

enter image description here

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

I'm having difficulty working out required values of resistors \$R_C\$ and \$R_E\$ in the circuit below. Can't seem to find any formulas on the web.

BJT Class A Circuit

I know how to find \$R_1\$ and \$R_2\$:

$$R_1 = (\frac{R_2}{V_B} \times V_{CC})-R_2$$

$$R_2 = \frac{β_{DC} \times R_E}{10}$$

I'd appreciate any help you can give with this as I can't move forward with other calculations until I find values for \$R_C\$ and \$R_E\$.

Technical specs of circuit:

  • BJT BC108
  • Voltage divider bias used
  • \$I_{C(sat)} = 20mA\$
  • \$V_{CC} = 10V\$
  • 10μF coupling capacitors for the input and output connections
  • 100μF capacitor for the bypass capacitor
  • \$β_{DC} ≈ 200\$
  • Voltage gain without bypass capacitor = 1.5

I plotted a DC Load Line and the Q-point is at \$I_C = 10mA\$ and \$V_{CE} = 5V\$.

enter image description here

4 Additional spec information
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3 MathJaXed the equations and improved overall formatting.
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