Timeline for How to arrange resistors for certain resistance
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Oct 5, 2017 at 9:02 | review | Close votes | |||
Oct 17, 2017 at 3:04 | |||||
Oct 5, 2017 at 8:45 | comment | added | Dmitry Grigoryev | Possible duplicate of Tool, algorithm or method to know which resistors to use for an equivalent resistance \$R_T\$? | |
Sep 28, 2015 at 17:21 | comment | added | user16324 | This does have an easy transformerless solution, though not all speakers receive the same power. | |
May 28, 2014 at 16:15 | comment | added | Christopher King | Wait, should I mark it as homework? It is an intermediate part of a homework problem. (Design a car audio system.) | |
May 28, 2014 at 14:34 | history | edited | JYelton | CC BY-SA 3.0 |
added 5 characters in body; edited title
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May 28, 2014 at 14:18 | answer | added | Andy aka | timeline score: 7 | |
May 28, 2014 at 14:15 | comment | added | Dave Tweed | How do you want the input power distributed among the speakers? Should they all get the same voltage, the same current, the same power, or some other distribution altogether? | |
May 28, 2014 at 14:12 | comment | added | Spehro 'speff' Pefhany | This looks like a homework problem, with the "speakers" used as a justification for them all being "powered". I can see at least one way to do it (with many trivial re-arrangements), given no constraint for them to be equally powered. Just play around with series-parallel resistances until you find a way. Hint: The one I came up with is 4||4. | |
May 28, 2014 at 14:07 | comment | added | Olin Lathrop | Are you sure your speakers have impedances of 1 and 2 Ohms? That is possible, but would be unusual. The vast majority of speakers are either 4 or 8 Ohms. | |
May 28, 2014 at 14:02 | history | asked | Christopher King | CC BY-SA 3.0 |