Skip to main content
7 events
when toggle format what by license comment
Jun 9, 2014 at 18:04 vote accept Xavier Hubbard Anderson
Jun 9, 2014 at 18:04
Jun 9, 2014 at 18:04 comment added Xavier Hubbard Anderson oh! i didn't know to do that! thanks for telling me!
Jun 9, 2014 at 15:09 comment added thomas.cloud That stuff is above my head, sorry I can't help anymore. Also, you should probably accept answers to some of your questions.
Jun 8, 2014 at 20:50 comment added Xavier Hubbard Anderson Is that true? the Law of mass action says that there should be less electrons in the P-doped region than in the N-doped region by several orders of magnitude. p*n = n_i^2 has to be conserved, right? so if we are introducing holes, we are removing electrons and vice-versa. Anyhow, I don't think the answer lies with the concentrations of charge carriers. I think it has to do with ohmic contact and schottky barriers. I'm just not sure what it is specifically yet.
Jun 8, 2014 at 17:35 comment added thomas.cloud The quantities of electrons are almost identical in both the SI-B & Si-P regions after the p/n junction has stabilized so no voltage would show up on a voltmeter. The electric field across the p/n junction remains b/c their are 9 protons (& 8 e-) in Si-P & 7 protons (& 8 e-) in Si-B setting up the charge differential (& E field along with it). I think it is important to understand the difference b/t the quantity of electrons & the charges of the molecules.
Jun 6, 2014 at 23:32 comment added Xavier Hubbard Anderson The chemistry perspective is helpful!! I've only ever seen this from an EE point of view. However, I understand conceptually why a space charge region exists in the PN-Junction. The bit I don't understand is why you cannot measure this built in voltage with an external meter! There was an answer on another question, but I wasn't satisfied with it.
Jun 6, 2014 at 16:26 history answered thomas.cloud CC BY-SA 3.0