Timeline for How does this single supply opamp circuit work, and what does the output look like?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Jun 23, 2014 at 11:46 | comment | added | Spehro 'speff' Pefhany | It is a function of input frequency, but above a few tens of Hz it hardly changes at all. Think of sqrt(R^2 + Xc^2).. If Xc << R then the exact value hardly matters. | |
| Jun 23, 2014 at 5:55 | comment | added | sherrellbc | Wouldn't the AC gain be a function of the input frequency since the reactance of C1 changes? | |
| Jun 23, 2014 at 5:18 | comment | added | Spehro 'speff' Pefhany | It will also work much better now that you edited it to have the supply pin connected to 9V rather than floating. ;-) Yes, your understanding is correct. In fact, at frequencies much above 1/(2*piRC) a capacitor in series with R can be ignored (so you just have R). | |
| Jun 23, 2014 at 1:47 | history | tweeted | twitter.com/#!/StackElectronix/status/480889798325198848 | ||
| Jun 23, 2014 at 1:32 | answer | added | gbarry | timeline score: 1 | |
| Jun 23, 2014 at 1:22 | vote | accept | Dave Branton | ||
| Jun 23, 2014 at 1:22 | history | edited | Dave Branton | CC BY-SA 3.0 |
added 691 characters in body
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| Jun 23, 2014 at 0:24 | answer | added | Spehro 'speff' Pefhany | timeline score: 3 | |
| Jun 23, 2014 at 0:04 | review | First posts | |||
| Jun 23, 2014 at 0:10 | |||||
| Jun 22, 2014 at 23:49 | history | asked | Dave Branton | CC BY-SA 3.0 |