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Sep 6, 2014 at 15:04 comment added Mister Mystère I think it's safe to say that attenuation is usually dominated by the losses in the cable. Some do not depend on the frequency (resistive losses), some do (inductive mainly). In order to be able to pick up a signal in spite of this repeaters can be used along the lines, or use stronger line drivers at the source.
Sep 6, 2014 at 13:45 comment added Fry attenuation might be the thing im looking for. so the attenuation could be a reason why one would use a linedriver in order to still being able to sent fast signals over longer lines ?
Sep 6, 2014 at 13:36 comment added Mister Mystère Except that the attenuation is not linear with frequency so more and more power would be needed. However you are right that I had analog bandwidth in mind and that topic seems to be about SPI, which is well explained by Andy. Still.
Sep 6, 2014 at 13:29 comment added Wouter van Ooijen Your main argument seems to be attenuation, but that can be solved by higher transmission power and/or a more sensitive receiver.
Sep 6, 2014 at 13:26 history edited Mister Mystère CC BY-SA 3.0
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Sep 6, 2014 at 13:17 history edited Mister Mystère CC BY-SA 3.0
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Sep 6, 2014 at 13:11 comment added Mister Mystère This analogy is not meant to be a match to bandwidth (I didn't find anything good enough for this), but to give an intuitive example on why distance is a factor in the achievable rate of the transmission of information. I edited the post to make it clearer, though I don't think it deserved a downvote.
Sep 6, 2014 at 13:05 history edited Mister Mystère CC BY-SA 3.0
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Sep 6, 2014 at 13:01 comment added Wouter van Ooijen In your analogy bandwidth would be the the number off pizza guys that can pass through a certain point per unit of time. I don't see how that would be affected by the delivery distance.
Sep 6, 2014 at 12:59 history answered Mister Mystère CC BY-SA 3.0