Timeline for LED Resistor, choosing resistor power
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 29, 2015 at 18:32 | vote | accept | Singe | ||
| Oct 29, 2015 at 17:33 | answer | added | Arsenal | timeline score: 3 | |
| Oct 29, 2015 at 17:26 | comment | added | Peter Bennett | You need the power dissipated in the resistor, so the calculation is Power = (V across resistor) times (Current through resistor). The resistor doesn't care about the power dissipated in the rest of the circuit. | |
| Oct 29, 2015 at 17:16 | comment | added | Nick Johnson | You know the current through the resistor, and you know the resistance across it. What happens if you multiply the two? And what when you multiply that by the current again? | |
| Oct 29, 2015 at 17:15 | comment | added | Eugene Sh. | Power = Current*Voltage. If you know the current and voltage drop on the resistor you know the power. | |
| Oct 29, 2015 at 17:14 | history | asked | Singe | CC BY-SA 3.0 |