Timeline for How to detect angular position of a device mounted on a rotating wheel?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 16, 2011 at 21:42 | vote | accept | avra | ||
| Oct 13, 2011 at 14:26 | comment | added | avra | @toybuilder: Thank for the info about 100-1000Hz accelerometers. I was not aware of their existance. With those speeds I think I can even handle properly distorsion data when car is breaking. | |
| Oct 13, 2011 at 14:22 | comment | added | avra | @stevenh: Sine should not be a problem. I know how to extract needed data from it. Thanks for nice tips. | |
| Oct 12, 2011 at 22:59 | comment | added | Toybuilder | 1000 rpm => roughly 10 hz. Given that the wheel spin is essentially constrained to one axis, you should be able to filter pick out peaks/valleys in the accelerometer output to detect when you're pointed more toward the ground or the sky. The bigger worry is the maximum load the accelerometer will support. There are a bunch of analog accelerometer's out there that should be able to give you closer to 100 or even 1kHz response, depending on your noise tolerance. | |
| Oct 12, 2011 at 7:44 | comment | added | stevenvh | @avra - a gyro won't detect the variation due to gravitation, that's what an accelerometer does. At the given speed the acceleration may be greater than the accelerometer's range, but this can be taken care of by placing the accelerometer at an angle, reducing it's sensitivity. You should still see the acceleration due to gravity as a sine superposed to the constant level due to the rotation. | |
| Oct 12, 2011 at 7:23 | comment | added | avra | At up to 1000 rpm I need more then 10 Hz digital gyro. Do you know of some super fast one? Can +1g and -1g be measured at 1000 rpm with strong centripetal force? Can constant centripetal force be eliminated by some math to extract directional vector? Do you have some link? Thank you very much for your valuable input. | |
| Oct 10, 2011 at 15:49 | history | answered | stevenvh | CC BY-SA 3.0 |