Timeline for How to combine two chip enable(/CE) signals into one with discrete components?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 29, 2015 at 11:21 | comment | added | user59864 | Wouldn't Shottky diodes be a better choice than ordinary silicon diodes if we mind the driver output voltage levels @ logical low? | |
| Dec 29, 2015 at 5:07 | comment | added | Sam Washburn | @IgnacioVazquez-Abrams The system clock is a little more than 1MHz. | |
| Dec 29, 2015 at 5:07 | comment | added | Krunal Desai | Looks like it is specified at 4 and 8mA -- definitely overthinking it, but figured it was worth it as a learning exercise. You're good with 10k unless I'm missing something exotic. | |
| Dec 29, 2015 at 5:04 | comment | added | pipe | @KrunalDesai The drivers are 74LS138 for the chip select lines. | |
| Dec 29, 2015 at 4:57 | comment | added | Ignacio Vazquez-Abrams | @SamWashburn: It depends on how quickly you need the signal to rise and how much current the diodes and memory controller output can handle. | |
| Dec 29, 2015 at 4:57 | comment | added | Krunal Desai | 10K is reasonable -- what's the current sinking capability of the driver? I can almost guarantee 10K is fine, but if you want to dot your i's and cross your t's, that's the thing to check. | |
| Dec 29, 2015 at 4:53 | comment | added | Sam Washburn | And I suppose a 10K pullup for a 5v supply? | |
| Dec 29, 2015 at 4:49 | comment | added | rdtsc | 1N4148 or similar small-signal diodes of course, not 1N4007's. :) | |
| Dec 29, 2015 at 4:49 | vote | accept | Sam Washburn | ||
| Dec 29, 2015 at 4:43 | history | answered | Ignacio Vazquez-Abrams | CC BY-SA 3.0 |