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Feb 10, 2012 at 17:13 vote accept supercat
Oct 25, 2011 at 13:52 answer added Russell McMahon timeline score: 0
Oct 25, 2011 at 1:56 answer added markrages timeline score: 1
Oct 24, 2011 at 17:34 answer added Russell McMahon timeline score: 1
Oct 24, 2011 at 17:24 history edited supercat CC BY-SA 3.0
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Oct 24, 2011 at 17:16 comment added supercat Sounds interesting, though it doesn't sound like it solves the problem with the device having occasional peak currents which are much higher than those one wants to measure. On the 1,000uA scale (which would be the one I'd probably use most) the series resistance is 10 ohms, which would drop a full volt at 100mA.
Oct 24, 2011 at 16:26 comment added vicatcu you should get a uCurrent from @eevblog... eevblog.com/projects/ucurrent or at least read about it :-)
Oct 24, 2011 at 16:12 history asked supercat CC BY-SA 3.0