Skip to main content
Electrical Engineering

Return to Answer

added 1 character in body
Source Link
Olin Lathrop
Olin Lathrop
  • 315k
  • 36
  • 441
  • 928

The rolloff frequency of a R-C filter is:

   F = 1 / (2πRC)

When R is in Ohms, C in Farads, then F is in Hz.

Therefore to get the capacitance is:

   C = 1 / (2πFC) = 1 / [2π(100 Hz)(10 kΩ)] = 160 nF

Yes, it's really that easy.

R-C rolloff filter calculations come up a lot in electronics. I keep 1/2π permanently in a register in my calculator. I can then divide that by two of the frequency, capacitance, or resistance to get the third.

The rolloff frequency of a R-C filter is:

   F = 1 / (2πRC)

When R is in Ohms, C in Farads, then F is in Hz.

Therefore to the capacitance is:

   C = 1 / (2πFC) = 1 / [2π(100 Hz)(10 kΩ)] = 160 nF

Yes, it's really that easy.

R-C rolloff filter calculations come up a lot in electronics. I keep 1/2π permanently in a register in my calculator. I can then divide that by two of the frequency, capacitance, or resistance to get the third.

The rolloff frequency of a R-C filter is:

   F = 1 / (2πRC)

When R is in Ohms, C in Farads, then F is in Hz.

Therefore to get the capacitance:

   C = 1 / (2πFC) = 1 / [2π(100 Hz)(10 kΩ)] = 160 nF

Yes, it's really that easy.

R-C rolloff filter calculations come up a lot in electronics. I keep 1/2π permanently in a register in my calculator. I can then divide that by two of the frequency, capacitance, or resistance to get the third.

Source Link
Olin Lathrop
Olin Lathrop
  • 315k
  • 36
  • 441
  • 928

The rolloff frequency of a R-C filter is:

  F = 1 / (2πRC)

When R is in Ohms, C in Farads, then F is in Hz.

Therefore to the capacitance is:

  C = 1 / (2πFC) = 1 / [2π(100 Hz)(10 kΩ)] = 160 nF

Yes, it's really that easy.

R-C rolloff filter calculations come up a lot in electronics. I keep 1/2π permanently in a register in my calculator. I can then divide that by two of the frequency, capacitance, or resistance to get the third.