Timeline for Is there any reason to use junction or Darlington transistors for power applications?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 14, 2023 at 19:47 | comment | added | Meymann | Late answer but I hope it helps: any switch requires protection (flywheel). Be it a BJT or a relay. That's not the point. Thumb rule: BJT for linear applications, MOSFET for switching. A darlington will still need a base resistor as its VBE is still around 1.4. Another thing that they don't tell you: Vce-Sat of a darlington is often well above 2V, which is a heartache if your VCC is 5v and a hot headache if you apply 5A on it. Yet, for linear applications - MOSFETS are a pain. They switch nicely but they are not my choice for a class A/B amp. | |
| Jun 27, 2016 at 10:07 | vote | accept | Dov | ||
| May 22, 2016 at 20:47 | comment | added | b degnan | The MOSFET is particularly susceptible to damage due to the gate oxide; however, BJTs can be damaged by a voltage spike, but you need a relatively large one, and the failure is the metal interface that connects the lead to the doped region. It's good policy to have a flyback diode on an inductive load to keep your power supply from bouncing, but strictly speaking, BJTs fail due to over current damaging the depletion region. A little extra charge across the device will just speed up recombination, but you are more likely to ruin the SnN "glue" that holds the wires on. | |
| S May 22, 2016 at 16:15 | history | suggested | Peter Mortensen | CC BY-SA 3.0 |
Copy edited.
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| May 22, 2016 at 16:08 | comment | added | Peter Mortensen | Why woldn't the BJT require protection when driving an inductive load? | |
| May 22, 2016 at 16:07 | review | Suggested edits | |||
| S May 22, 2016 at 16:15 | |||||
| May 22, 2016 at 10:59 | history | answered | b degnan | CC BY-SA 3.0 |