In an op-amp (non-inverting), 
when Vs\$V_s\$ increases by delta_v\$\Delta V\$, Vn\$V_n\$ approaches Vp\$V_p\$ until the difference is delta_v / A\$\Delta V/ A\$ (where A is infinity)(where A is infinity).
Why is there the delta_v / A\$\Delta V/ A\$ difference and where does this difference come from? Why does it equal the specific value delta_v / A? Why doesn't V_n\$V_n\$ just equal V_p\$V_p\$ (so that the difference is 0)?
In an op-amp (non-inverting),
when Vs increases by delta_v, Vn approaches Vp until the difference is delta_v / A (where A is infinity).
Why is there the delta_v / A difference and where does this difference come from? Why does it equal the specific value delta_v / A? Why doesn't V_n just equal V_p (so that the difference is 0)?
In an op-amp (non-inverting),
when \$V_s\$ increases by \$\Delta V\$, \$V_n\$ approaches \$V_p\$ until the difference is \$\Delta V/ A\$ (where A is infinity).
Why is there the \$\Delta V/ A\$ difference and where does this difference come from? Why doesn't \$V_n\$ just equal \$V_p\$ (so that the difference is 0)?
In an op-amp (non-inverting),
when Vs increases by delta_v, Vn approaches Vp until the difference is delta_v / A (where A is infinity).
Why is there the delta_v / A difference and where does this difference come from? Why does it equal the specific value delta_v / A? Why doesn't V_n just equal V_p (so that the difference is 0)?
