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In this case you already represent both in the same terms (cosine) so you can see which one is leading by seeing which phase is greater. In this case v1(t) = 4cos(377t + 10)\$v1(t) = 4*\cos(377t + 10)\$ and v2 = +20cos (377t+180)\$v2 = +20*cos (377t+180)\$. You can see that v2 has greater phase (180) than v1 (10). Now you know that V2 is leading V1 by 170 (180-10).

In this case you already represent both in the same terms (cosine) so you can see which one is leading by seeing which phase is greater. In this case v1(t) = 4cos(377t + 10) and v2 = +20cos (377t+180). You can see that v2 has greater phase (180) than v1 (10). Now you know that V2 is leading V1 by 170 (180-10).

In this case you already represent both in the same terms (cosine) so you can see which one is leading by seeing which phase is greater. In this case \$v1(t) = 4*\cos(377t + 10)\$ and \$v2 = +20*cos (377t+180)\$. You can see that v2 has greater phase (180) than v1 (10). Now you know that V2 is leading V1 by 170 (180-10).

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In this case you already represent both in the same terms (cosine) so you can see which one is leading by seeing which phase is greater. In this case v1(t) = 4cos(377t + 10) and v2 = +20cos (377t+180). You can see that v2 has greater phase (180) than v1 (10). Now you know that V2 is leading V1 by 170 (180-10).