Timeline for AC Circuit Having Only Capacitor
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 16, 2017 at 23:38 | history | edited | Enric Blanco | CC BY-SA 3.0 |
deleted 10 characters in body
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| Apr 16, 2017 at 22:28 | history | edited | Enric Blanco | CC BY-SA 3.0 |
deleted 45 characters in body
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| Apr 16, 2017 at 22:03 | history | edited | Enric Blanco | CC BY-SA 3.0 |
formatting enhanced, non-answer content trimmed
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| Feb 20, 2017 at 8:42 | vote | accept | Perspicacious | ||
| Feb 20, 2017 at 8:42 | comment | added | Perspicacious | Enric I got u. I got u. Thanks a lot. You made my day. Thank you very much | |
| Feb 19, 2017 at 12:22 | history | edited | Enric Blanco | CC BY-SA 3.0 |
Additional explanations for the OP
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| Feb 19, 2017 at 10:58 | comment | added | Enric Blanco | Now I see where your problem is: your mathematical approach is flawed. You're confused about small increments. I'll edit my answer to explain it to you. | |
| Feb 19, 2017 at 6:31 | comment | added | Perspicacious | but if it's true at any instant then how current is flowing in the circuit. In DC, if applied emf becomes equal to the voltage of capacitor then DC stops /we say the capacitor is fully charged. In Ac if we talk about that very small instant of time(where we assume that the applied emf is constant), then the scenario is same as in case of DC. And Current should not flow. Sorry if I didn't get ur point | |
| Feb 19, 2017 at 2:53 | history | answered | Enric Blanco | CC BY-SA 3.0 |