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Apr 12, 2017 at 6:37 comment added winny You only use your potentiometer to set the value, then replace it with a fixed resistor.
Apr 12, 2017 at 5:44 comment added deki I'm worried about noise, since this will be used for an application that requires minimal noise. I've already tried to optimise it for as little noise as possible, and don't want to have my output affected by a poteniometer. I've updated my post to include a formula I found.
Apr 12, 2017 at 5:22 history answered winny CC BY-SA 3.0