Timeline for The gain of a non-inverting op amp
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| May 8, 2017 at 17:01 | comment | added | Kevin White | The Thevenin equivalent is the effective resistance that the bias current sees (that is the feedback resistance and the resistor to ground in parallel) However you're right in that you don't need it. The drop across the feedback resistor is independent of the resistor to ground. | |
| May 8, 2017 at 17:00 | history | edited | Kevin White | CC BY-SA 3.0 |
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| May 8, 2017 at 16:59 | comment | added | Moeen Ahmed | Oh I got it. When they say a source resistance of 5k, they do not mean the resistor on the inverting lead/wire. They mean 5k is the resistance of a source voltage attached to the non-inverting lead/wire. The resistance attached to the inverting lead can be calculated using the formula Vo/Vi=1+(R2/R1), where R1 is the unknown resistance on the inverting lead. The wording of this question is very terrible. | |
| May 8, 2017 at 16:41 | comment | added | LvW | I do not think, that the Thevenin equivalent is meant. For which purpose? This would make no sense at all. | |
| May 8, 2017 at 16:40 | history | edited | Kevin White | CC BY-SA 3.0 |
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| May 8, 2017 at 16:03 | history | answered | Kevin White | CC BY-SA 3.0 |