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Edited to expand non ideal case.
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Assuming they are ideal diodes with a Vd of 0.7:

D1 will be forward biased so Vr1 is 4.301V

D2 will not be forward biased, so no current will flow since V-dV - 4.301 = 0,698; which is not enough to forward bias your ideal diode.

Vb in pictur is Vd in my comment

If the diodes where real, Vd would not be exactly 0.7 and the I-V relation would not be a vertical straight line, it would be a non-linear funcion with a slope affected by temperature and other factors. Wikipedia article "Shockley diode equation" covers it. Also noise in the power supplies should be taken into account. Summarizing, a lot more to take care of.

Assuming they are ideal diodes with a Vd of 0.7:

D1 will be forward biased so Vr1 is 4.301V

D2 will not be forward biased, so no current will flow since V-dV - 4.301 = 0,698; which is not enough to forward bias your ideal diode.

Vb in pictur is Vd in my comment

Assuming they are ideal diodes with a Vd of 0.7:

D1 will be forward biased so Vr1 is 4.301V

D2 will not be forward biased, so no current will flow since V-dV - 4.301 = 0,698; which is not enough to forward bias your ideal diode.

Vb in pictur is Vd in my comment

If the diodes where real, Vd would not be exactly 0.7 and the I-V relation would not be a vertical straight line, it would be a non-linear funcion with a slope affected by temperature and other factors. Wikipedia article "Shockley diode equation" covers it. Also noise in the power supplies should be taken into account. Summarizing, a lot more to take care of.

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Assuming they are ideal diodes with a Vd of 0.7:

D1 will be forward biased so Vr1 is 4.301V

D2 will not be forward biased, so no current will flow since V-dV - 4.301 = 0,698; which is not enough to forward bias your ideal diode.

Vb in pictur is Vd in my comment