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Sep 28, 2019 at 17:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
May 30, 2019 at 15:08 comment added D.A.S. How not to design a cascode amp. Values and ratios are critical. THis example has no gain
May 30, 2019 at 14:01 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 28, 2019 at 5:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Nov 4, 2017 at 20:31 comment added jonk Well, you have wires going "off sheet" and I pretty much don't know what you are trying to achieve. There seems to be a "stream of consciousness" but for some reason I can't convert it into a mental picture that is concrete enough. Could just be me. I do see \$Q_1\$ and \$Q_2\$ as the diff-amp pair, \$Q_3\$ and \$Q_4\$ as your cascodes, and \$Q_5\$ and \$Q_6\$ as the mirror pair. The wire from collectors of \$Q_3\$ and \$Q_6\$, heading off to the right, carries the diff current. Fine. But no real specs, just random hacked values. So I've no idea what to suggest.
Nov 4, 2017 at 11:56 comment added Tyler Lungrin Don't pay attention to the values, once it first didnt work I started changing them randomly just to see what would happen.
Nov 4, 2017 at 5:27 comment added jonk When assumed balanced and I take half of your \$50\:\textrm{mA}\$ and multiply it by your mirrors' \$470\:\Omega\$ I get almost \$V_{SS}+12\:\textrm{V}\$ at the emitters of \$Q_6\$ and \$Q_5\$. Was that intended?
Nov 4, 2017 at 4:28 answer added analogsystemsrf timeline score: 1
Nov 3, 2017 at 23:24 history asked Tyler Lungrin CC BY-SA 3.0