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Feb 14, 2018 at 21:38 vote accept circuitry
Jan 31, 2018 at 19:46 comment added circuitry I'm also not really sure what would happen if my circuit cannot provide enough current. I would imagine that could result in the signal cutting in and out which would not be ideal.
Jan 31, 2018 at 19:45 comment added circuitry The intention is to make sure I'm not damaging my amplifier or speakers. The PLX 3602 is capable of outputting 3,600 watts. In my use case I am going to be outputting 1250 watts (4 ohms, single channel). I need to make sure I don't fry my speakers or amp, so I'm trying to make sure the signal I send to my amplifier is within the acceptable input voltage range so it doesn't result in clipping.
Jan 31, 2018 at 19:36 comment added Transistor That figure is telling you that you will get the rated output into 8 Ω speakers with that level on the 10 kΩ input. Your ear has a logarithmic response to volume. Double the volume requires ten times the power. Turn the volume down and plug it in. Given that you're generating the sound from an Arduino I'd say you or your audience aren't going to listen to it for very long so I wouldn't waste too much time on the calculations.
Jan 31, 2018 at 19:33 comment added circuitry In that event it seems like I would do (1.25/10k)*1000, and the current would be 0.125 mA. I am going to be driving a 4 ohm speaker though so I'm not sure if that would change things.
Jan 31, 2018 at 19:31 comment added circuitry Hmm I'm looking at qsc.com/resource-files/productresources/amp/plx2/…, for PLX3602. It says "input sensitivity at 8 ohms", but it also says "input impedance 10 kohms unbalanced, 20 kohms balanced."
Jan 31, 2018 at 19:24 comment added Transistor Surely the 8 Ω refers to the amplifier output impedance?
Jan 31, 2018 at 19:06 comment added circuitry My amplifier's input sensitivity is 1.25 Vrms at 8 ohms. Does this mean I need to be able to source 156 mA (1.25/8)*1000?
Jan 31, 2018 at 18:37 history answered Transistor CC BY-SA 3.0