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WARNING! To others reading this question: This circuit uses high voltage. DO NOT mess with 220V/110V unless you know what you're doing and know the risks (electrocution and death, mainly)

Now that that's out of way...

Hello everyone, I'll try to be as brief as possible: I have a heating element taken from a 220V hot plate and connected like so:

Original circuit

Components:
Vs: 220V (RMS) 50Hz sine AC (from wall outlet)
U1: Bog standard DIAC-TRIC dimmer
R1: The heating element, 100 Ohms in room temperature (assumed more when hot)
R2: A very small incandescent light bulb, also taken from the hot plate, I assume it'sits current is negligible

I need to slightly reduce the current of the heating element. I thought about a non polarized 100V 100uF capacitor but I don't have one. I do have 50V 1000uF polarized capacitors, so, my first question: If identical capacitors in series have their max allowable voltages added up but their capacity divided by the number of capacitors, AND, if 2 identical polarized capacitors connected in series with reverse polarity make a non polarized capacitor with half the capacity (reference), then, will connecting eight 50V 1000uF polarized capacitors back to back create the equivalent of a single 200V 125uF bi-polar capacitor?

The new schematic:

"Improved" circuit

New components:
C1 - C8: Radial aluminum electrolytic polarized 50V 1000uF capacitors

So if my calculations are correct, when the dimmer is at full and the element is at room temperature, the capacitors will measure 63V at peak amplitude and will reduce the RMS current by 447mA (2.2A without the capacitors, 1.753A with them).

Second question: Is everything I wrote correct? Or did I accidentally build the equivalent of a hydrogen bomb that will destroy my house, neighborhood, and everyone I've ever known and loved??

WARNING! To others reading this question: This circuit uses high voltage. DO NOT mess with 220V/110V unless you know what you're doing and know the risks (electrocution and death, mainly)

Now that that's out of way...

Hello everyone, I'll try to be as brief as possible: I have a heating element taken from a 220V hot plate and connected like so:

Original circuit

Components:
Vs: 220V (RMS) 50Hz sine AC (from wall outlet)
U1: Bog standard DIAC-TRIC dimmer
R1: The heating element, 100 Ohms in room temperature (assumed more when hot)
R2: A very small incandescent light bulb, also taken from the hot plate, I assume it's current is negligible

I need to slightly reduce the current of the heating element. I thought about a non polarized 100V 100uF capacitor but I don't have one. I do have 50V 1000uF polarized capacitors, so, my first question: If identical capacitors in series have their max allowable voltages added up but their capacity divided by the number of capacitors, AND, if 2 identical polarized capacitors connected in series with reverse polarity make a non polarized capacitor with half the capacity (reference), then, will connecting eight 50V 1000uF polarized capacitors back to back create the equivalent of a single 200V 125uF bi-polar capacitor?

The new schematic:

"Improved" circuit

New components:
C1 - C8: Radial aluminum electrolytic polarized 50V 1000uF capacitors

So if my calculations are correct, when the dimmer is at full and the element is at room temperature, the capacitors will measure 63V at peak amplitude and will reduce the RMS current by 447mA (2.2A without the capacitors, 1.753A with them).

Second question: Is everything I wrote correct? Or did I accidentally build the equivalent of a hydrogen bomb that will destroy my house, neighborhood, and everyone I've ever known and loved??

WARNING! To others reading this question: This circuit uses high voltage. DO NOT mess with 220V/110V unless you know what you're doing and know the risks (electrocution and death, mainly)

Now that that's out of way...

Hello everyone, I'll try to be as brief as possible: I have a heating element taken from a 220V hot plate and connected like so:

Original circuit

Components:
Vs: 220V (RMS) 50Hz sine AC (from wall outlet)
U1: Bog standard DIAC-TRIC dimmer
R1: The heating element, 100 Ohms in room temperature (assumed more when hot)
R2: A very small incandescent light bulb, also taken from the hot plate, I assume its current is negligible

I need to slightly reduce the current of the heating element. I thought about a non polarized 100V 100uF capacitor but I don't have one. I do have 50V 1000uF polarized capacitors, so, my first question: If identical capacitors in series have their max allowable voltages added up but their capacity divided by the number of capacitors, AND, if 2 identical polarized capacitors connected in series with reverse polarity make a non polarized capacitor with half the capacity (reference), then, will connecting eight 50V 1000uF polarized capacitors back to back create the equivalent of a single 200V 125uF bi-polar capacitor?

The new schematic:

"Improved" circuit

New components:
C1 - C8: Radial aluminum electrolytic polarized 50V 1000uF capacitors

So if my calculations are correct, when the dimmer is at full and the element is at room temperature, the capacitors will measure 63V at peak amplitude and will reduce the RMS current by 447mA (2.2A without the capacitors, 1.753A with them).

Second question: Is everything I wrote correct? Or did I accidentally build the equivalent of a hydrogen bomb that will destroy my house, neighborhood, and everyone I've ever known and loved??

Source Link

Reducing voltage/current of AC circuit with makeshift bi-polar capacitor

WARNING! To others reading this question: This circuit uses high voltage. DO NOT mess with 220V/110V unless you know what you're doing and know the risks (electrocution and death, mainly)

Now that that's out of way...

Hello everyone, I'll try to be as brief as possible: I have a heating element taken from a 220V hot plate and connected like so:

Original circuit

Components:
Vs: 220V (RMS) 50Hz sine AC (from wall outlet)
U1: Bog standard DIAC-TRIC dimmer
R1: The heating element, 100 Ohms in room temperature (assumed more when hot)
R2: A very small incandescent light bulb, also taken from the hot plate, I assume it's current is negligible

I need to slightly reduce the current of the heating element. I thought about a non polarized 100V 100uF capacitor but I don't have one. I do have 50V 1000uF polarized capacitors, so, my first question: If identical capacitors in series have their max allowable voltages added up but their capacity divided by the number of capacitors, AND, if 2 identical polarized capacitors connected in series with reverse polarity make a non polarized capacitor with half the capacity (reference), then, will connecting eight 50V 1000uF polarized capacitors back to back create the equivalent of a single 200V 125uF bi-polar capacitor?

The new schematic:

"Improved" circuit

New components:
C1 - C8: Radial aluminum electrolytic polarized 50V 1000uF capacitors

So if my calculations are correct, when the dimmer is at full and the element is at room temperature, the capacitors will measure 63V at peak amplitude and will reduce the RMS current by 447mA (2.2A without the capacitors, 1.753A with them).

Second question: Is everything I wrote correct? Or did I accidentally build the equivalent of a hydrogen bomb that will destroy my house, neighborhood, and everyone I've ever known and loved??