Timeline for Reducing voltage/current of AC circuit with makeshift bi-polar capacitor
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 28, 2018 at 5:41 | vote | accept | C4lculated | ||
| Mar 27, 2018 at 13:02 | answer | added | Andy aka | timeline score: 1 | |
| Mar 27, 2018 at 11:43 | comment | added | C4lculated | Why was my question downvoted? Did I do something wrong? Please explain my mistakes to me so that I can avoid making them again. | |
| Mar 27, 2018 at 11:29 | comment | added | C4lculated | MCG: Is there a downside to this impedance? Brian Drummond: The dimmer is a built product, not a circuit by me and I don't want to modify it. Neil_UK: I want to reduce the whole range, I.E. I want a lower current at both the minimum and the maximum values of the dimmer. I hope I managed to explain it correctly now. | |
| Mar 27, 2018 at 10:46 | comment | added | Neil_UK | Why do you need to reduce the current of the heating element, when it's already connected to a device for reducing its power? Is it necessary, or will your capacitors be sufficient, for the problem you actually have, rather than the one you state? | |
| Mar 27, 2018 at 10:44 | history | edited | Neil_UK | CC BY-SA 3.0 |
it's
|
| Mar 27, 2018 at 10:42 | comment | added | user16324 | Better to just control the dimmer range, surely? | |
| Mar 27, 2018 at 10:19 | comment | added | MCG | You know you'll be adding a lot of impedance to the circuit by introducing all those capacitors don't you? | |
| Mar 27, 2018 at 10:00 | review | First posts | |||
| Mar 27, 2018 at 11:17 | |||||
| Mar 27, 2018 at 9:59 | history | asked | C4lculated | CC BY-SA 3.0 |