Timeline for Output voltage of USB FAN
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 24, 2019 at 8:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 24, 2019 at 3:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 16, 2019 at 23:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jun 9, 2018 at 13:44 | answer | added | Jim Fischer | timeline score: 1 | |
| Jun 9, 2018 at 11:35 | answer | added | HarryH | timeline score: 0 | |
| Jun 9, 2018 at 10:56 | comment | added | Vladimir Cravero | also, what is the voltage of that GPIO? if it is a 1.8 V pin, you need a much lower base resistor. | |
| Jun 9, 2018 at 10:03 | answer | added | gabonator | timeline score: 0 | |
| Jun 9, 2018 at 9:50 | comment | added | Jim Fischer | As a starting point, determine the current the load (the fan) requires, which is the BJT's collector current IC. The BJT's base current needs to be IB=IC/Beta(sat). For a power BJT Beta(sat) is typically somewhere between 4 and 10; check the datasheet to determine the value of Beta(sat) that the mfgr uses for parametric testing. You'll need to adjust the resistor value to permit a current of IB amps from the DIO pin into the BJT's base. IIRC, a DIO pin can source current up to 40 ma, max, for a logic high output. | |
| Jun 9, 2018 at 9:39 | history | edited | Hasan | CC BY-SA 4.0 |
edited title
|
| Jun 9, 2018 at 9:32 | history | asked | Hasan | CC BY-SA 4.0 |