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Oct 28, 2018 at 19:10 history edited Misunderstood CC BY-SA 4.0
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Oct 28, 2018 at 19:05 history edited Misunderstood CC BY-SA 4.0
added 159 characters in body
Oct 28, 2018 at 18:59 history edited Misunderstood CC BY-SA 4.0
added 159 characters in body
Oct 28, 2018 at 18:52 history edited Misunderstood CC BY-SA 4.0
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Oct 28, 2018 at 18:39 history edited Misunderstood CC BY-SA 4.0
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Oct 28, 2018 at 18:20 comment added Misunderstood A picture is worth a thousand words. See update two.
Oct 28, 2018 at 18:20 history edited Misunderstood CC BY-SA 4.0
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Oct 28, 2018 at 16:52 comment added Frayt I have included a picture with some updated readings
Oct 27, 2018 at 18:38 comment added Frayt Thanks. To answer quickly: The LED is of the first type and under a magnifying glass you can see three individual "elements" within the LED. The 22 ohm resistor was sufficient but as bright as an unmodified circuit board. I'll get back to you with some photos tomorrow.
Oct 27, 2018 at 17:35 history edited Misunderstood CC BY-SA 4.0
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Oct 27, 2018 at 17:26 comment added Misunderstood See update to my answer.
Oct 27, 2018 at 17:25 history edited Misunderstood CC BY-SA 4.0
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Oct 27, 2018 at 17:14 history edited Misunderstood CC BY-SA 4.0
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Oct 27, 2018 at 17:11 comment added Frayt Using a 47Ω results in the LED being dimmer than it would be on an unmodified circuit board (I have an identical light which I can use for comparisons). 100Ω and above do not burn out at all. Also, to clarify, the LED is normally white, not blue, and I understand the colour change to blue is because of excess current.
Oct 27, 2018 at 17:08 history answered Misunderstood CC BY-SA 4.0