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Michel Keijzers
Michel Keijzers
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burst Burst mode in synchronous buck converter with current mode control?

I read this previous question:

The meaning of Burst Mode

It says burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. However, I just cannot understand how the light load decreases the load current and therefore the inductor current, as mentioned in the link.

As I know \$Vload=Rload*Iload\$ and \$Vload=D*Vin\$. So if we have a low load and highest input voltage, this implies that the duty cycle is small and the current is going high - which means the inductor current must be high as well and never goesgo to DCM! 

What I am missing?

burst mode in synchronous buck converter with current mode control?

I read this previous question:

The meaning of Burst Mode

It says burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. However I just cannot understand how the light load decreases the load current and therefore the inductor current, as mentioned in the link.

As I know \$Vload=Rload*Iload\$ and \$Vload=D*Vin\$. So if we have low load and highest input voltage, this implies that duty cycle is small and the current is going high - which means the inductor current must be high as well and never goes to DCM! What I am missing?

Burst mode in synchronous buck converter with current mode control?

I read this previous question:

The meaning of Burst Mode

It says burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. However, I just cannot understand how the light load decreases the load current and therefore the inductor current, as mentioned in the link.

As I know \$Vload=Rload*Iload\$ and \$Vload=D*Vin\$. So if we have a low load and highest input voltage, this implies that the duty cycle is small and the current is going high - which means the inductor current must be high as well and never go to DCM! 

What I am missing?

Used MathJAX formatting for the formulas (some "*" characters were not being displayed, and were instead changing text to italics, due to Markdown syntax). Some other grammar changes and text splitting, to improve readability.
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SamGibson ♦
SamGibson ♦
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as I read in the link followingthis previous question:   

enter link description hereThe meaning of Burst Mode

theIt says burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. butHowever I just cannot understand how does the light load decreases the load current and therefore the inductor current, as mentioned in the link. As

As I know Vload=RloadIload and Vload=DVin\$Vload=Rload*Iload\$ and \$Vload=D*Vin\$. so IfSo if we have low load and highest input voltage, this implies that duty cycle is so small and thethe current is going high - which means the inductor current must be high as well and never goes to DCM!!! whatWhat I am missing?

as I read in the link following:  enter link description here

the burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. but I just cannot understand how does the light load decreases the load current and therefore the inductor current as mentioned in the link. As I know Vload=RloadIload and Vload=DVin. so If we have low load and highest input voltage, this implies that duty cycle is so small and the current is going high which means the inductor current must be high as well and never goes to DCM!!! what I am missing?

I read this previous question: 

The meaning of Burst Mode

It says burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. However I just cannot understand how the light load decreases the load current and therefore the inductor current, as mentioned in the link.

As I know \$Vload=Rload*Iload\$ and \$Vload=D*Vin\$. So if we have low load and highest input voltage, this implies that duty cycle is small and the current is going high - which means the inductor current must be high as well and never goes to DCM! What I am missing?

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Yaakov
Yaakov
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burst mode in synchronous buck converter with current mode control?

as I read in the link following: enter link description here

the burst mode happens when the resistance of the load is light and the system stops switching the MOSFETs. but I just cannot understand how does the light load decreases the load current and therefore the inductor current as mentioned in the link. As I know Vload=RloadIload and Vload=DVin. so If we have low load and highest input voltage, this implies that duty cycle is so small and the current is going high which means the inductor current must be high as well and never goes to DCM!!! what I am missing?