Skip to main content
5 events
when toggle format what by license comment
Sep 22, 2012 at 23:27 vote accept kbarber
Sep 21, 2012 at 11:49 comment added kbarber Okay - I assumed (A-B) was subtraction - I just wanted to be sure that there wasn't an explicit setting to place the scope in this mode and that using the calculation was sufficient. Do you happen to know if there is a difference between current-sense and shunt resistors?
Sep 21, 2012 at 1:56 comment added Oli Glaser The "A-B" refers to the subtraction (differential) mode. Set it to this and connect one probe to each pin. The scope will display the voltage across the shunt resistor, and the current is V / Rshunt.
Sep 21, 2012 at 0:00 comment added kbarber I forgot to mention that when the jumper is removed, VCCINT of the core is tied to a current-sense resistor. Looking at the definition of current-sense vs. shunt, for these purposes, seem to be relatively close (please correct me if I'm wrong) - so I think that will take care of the first part of this solution. For the differential measurement - I don't explicitly see a "differential mode" setting (I have an Agilent InfiniiVision) but there is a math function to subtract one channel from another - is this sufficient? Thanks!
Sep 20, 2012 at 22:35 history answered Dave Tweed CC BY-SA 3.0