3 added 43 characters in body edited Feb 15 at 12:53 Tom Carpenter 41.4k33 gold badges8282 silver badges126126 bronze badges The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which are commonly available for commercial light switches. In the UK these are called "1 gang 2 way". When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. As pointed out in the comments, this circuit should only be used as shown above, with a common live. If you house has more than one live phase, make sure both lamps are on the same phase and fuse/breaker. The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which are commonly available for commercial light switches. When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. As pointed out in the comments, this circuit should only be used as shown above, with a common live. If you house has more than one live phase, make sure both lamps are on the same phase and fuse/breaker. The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which are commonly available for commercial light switches. In the UK these are called "1 gang 2 way". When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. As pointed out in the comments, this circuit should only be used as shown above, with a common live. If you house has more than one live phase, make sure both lamps are on the same phase and fuse/breaker. 2 added 207 characters in body edited Feb 15 at 7:58 Tom Carpenter 41.4k33 gold badges8282 silver badges126126 bronze badges The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which is pretty standardare commonly available for most commercial light switches. When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. As pointed out in the comments, this circuit should only be used as shown above, with a common live. If you house has more than one live phase, make sure both lamps are on the same phase and fuse/breaker. The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which is pretty standard for most commercial light switches. When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which are commonly available for commercial light switches. When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1. As pointed out in the comments, this circuit should only be used as shown above, with a common live. If you house has more than one live phase, make sure both lamps are on the same phase and fuse/breaker. 1 answered Feb 14 at 23:42 Tom Carpenter 41.4k33 gold badges8282 silver badges126126 bronze badges The following should work based on your comments: simulate this circuit – Schematic created using CircuitLab This requires that SW1 is a SPDT switch, which is pretty standard for most commercial light switches. When SW1 is turned on, it will turn on L1 only. When the PIR is turned on, it will turn on either both L1 and L2 (if SW1 is off), or just L2 (if SW1 is on). SW1 PIR | Lamp1 Lamp2 -----------+---------------- Off Off | Off Off On Off | On Off Off On | On On On On | On On  This means that both L1 and L2 will be illuminated by the PIR regardless of SW1. And only L1 will be controlled by SW1.