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Mar 10, 2019 at 17:53 answer added kch_PE_MSEE_BSCE timeline score: 1
Mar 10, 2019 at 15:16 answer added AnalogKid timeline score: 0
Mar 10, 2019 at 15:13 answer added Hearth timeline score: 0
Mar 10, 2019 at 14:57 comment added Hearth @SparklingWater Put the FET on the low side instead of the high side then.
Mar 10, 2019 at 14:29 comment added SparklingWater Correct. I didn't edit the standard values in the software. But then it still is not replaced the way I wanted to, since the gate voltage with the switch is higher than the other voltage source.
Mar 10, 2019 at 14:22 comment added Hearth What's your source voltage? The gate voltage of the high side FET needs to be higher than that (by a margin that depends on the exact device) to turn it fully on.
Mar 10, 2019 at 14:14 history edited SparklingWater CC BY-SA 4.0
proposed solution
Mar 10, 2019 at 11:17 comment added Transistor For a start, you'll need two switches - one to charge, one to discharge.
Mar 10, 2019 at 11:00 review First posts
Mar 10, 2019 at 12:02
Mar 10, 2019 at 10:55 history asked SparklingWater CC BY-SA 4.0