Consider a "small" autonomous grid, which is based mainly on RES and has a few diesel generators, like in the following figure

Everything runs smoothly, feeding the small load. Suddenly, the big angry load tries to connect and its transformer draws a large magnetization current (let's say 3 or 4 times the nominal current).

My question is: Is there a reliable strategy to follow so that the DC/AC converter manage that current without shutting down? Obviously, there will be a current limiting function, but is it fast enough?

Some conditions

• Load's transformer in inaccessible
• We cannot depend only on the diesel generators to supply that current
• We want to avoid a partial shut down of the system
• Voltage drop, for 10-15 cycles is allowed

I know the question is broad and the answer depends on various parameters, but is there an "standard" method to deal with this problem?

EDIT

The nominal current is not strictly specified, but if we consider that the big load is ~ 1MW @ 400 phase-phase, the current is \$ I = \frac{1MW/3}{\sqrt3 \cdot 400} = 480 A \$

Consider a "small" autonomous grid, which is based mainly on RES and has a few diesel generators, like in the following figure

Everything runs smoothly, feeding the small load. Suddenly, the big angry load tries to connect and its transformer draws a large magnetization current (let's say 3 or 4 times the nominal current).

My question is: Is there a reliable strategy to follow so that the DC/AC converter manage that current without shutting down? Obviously, there will be a current limiting function, but is it fast enough?

Some conditions

• Load's transformer in inaccessible
• We cannot depend only on the diesel generators to supply that current
• We want to avoid a partial shut down of the system
• Voltage drop, for 10-15 cycles is allowed

I know the question is broad and the answer depends on various parameters, but is there an "standard" method to deal with this problem?

EDIT

The nominal current is not strictly specified, but if we consider that the big load is ~ 1MW @ 400 phase-phase, the current is \$ I = \frac{1MW/3}{\sqrt3 \cdot 400} = 480 A \$

EDIT #2

The big load is mostly resistive - it heats up water. There may be some motors, but this is not the issue.

Consider a "small" autonomous grid, which is based mainly on RES and has a few diesel generators, like in the following figure

Everything runs smoothly, feeding the small load. Suddenly, the big angry load tries to connect and its transformer draws a large magnetization current (let's say 3 or 4 times the nominal current).

My question is: Is there a reliable strategy to follow so that the DC/AC converter manage that current without shutting down? Obviously, there will be a current limiting function, but is it fast enough?

Some conditions

• Load's transformer in inaccessible
• We cannot depend only on the diesel generators to supply that current
• We want to avoid a partial shut down of the system
• Voltage drop, for 10-15 cycles is allowed

I know the question is broad and the answer depends on various parameters, but is there an "standard" method to deal with this problem?

Consider a "small" autonomous grid, which is based mainly on RES and has a few diesel generators, like in the following figure

Everything runs smoothly, feeding the small load. Suddenly, the big angry load tries to connect and its transformer draws a large magnetization current (let's say 3 or 4 times the nominal current).

My question is: Is there a reliable strategy to follow so that the DC/AC converter manage that current without shutting down? Obviously, there will be a current limiting function, but is it fast enough?

Some conditions

• Load's transformer in inaccessible
• We cannot depend only on the diesel generators to supply that current
• We want to avoid a partial shut down of the system
• Voltage drop, for 10-15 cycles is allowed

I know the question is broad and the answer depends on various parameters, but is there an "standard" method to deal with this problem?

EDIT

The nominal current is not strictly specified, but if we consider that the big load is ~ 1MW @ 400 phase-phase, the current is \$ I = \frac{1MW/3}{\sqrt3 \cdot 400} = 480 A \$