Timeline for Class A amplifier - Transistor Q-Point calculation
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 12, 2019 at 15:39 | comment | added | G36 | Ieq = emitter quiescent current | |
| Jun 12, 2019 at 15:12 | comment | added | user3728501 | Ok, and Ieq IS that current that the base takes, and it is called the "quiescent current"? | |
| Jun 12, 2019 at 15:07 | comment | added | Andy aka | You need to calculate the ESR because the small amount of base current turns what should be a perfect 3 volts into something closer to 2.9 volts (or thereabouts). The base takes current because \$\beta\$ is not infinity. If beta were infinity (or the resistors R1 and R2 were very much lower in value), exactly 3 volts would be applied to the base and the formula would be much simpler. | |
| Jun 12, 2019 at 15:01 | comment | added | Andy aka | I've added a link to Thevenin's theorem | |
| Jun 12, 2019 at 15:00 | history | edited | Andy aka | CC BY-SA 4.0 |
added 104 characters in body
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| Jun 12, 2019 at 14:59 | comment | added | user3728501 | I followed everything there up to a point: I think no I don't know what effective series resistance is exactly, although I do know how to calculate it just not "why". You raise a new question however which is where does that formula for Ieq come from? And what does Ieq actually mean? Is it the quiescent current? | |
| Jun 12, 2019 at 14:54 | history | answered | Andy aka | CC BY-SA 4.0 |