Timeline for how can I calculate the smallest measurable voltage for a given adc?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 24, 2019 at 15:19 | vote | accept | Hegedus.Cs | ||
| Dec 24, 2019 at 5:48 | answer | added | D.A.S. | timeline score: 2 | |
| Dec 24, 2019 at 5:43 | answer | added | DKNguyen | timeline score: 0 | |
| Dec 24, 2019 at 5:36 | answer | added | user1850479 | timeline score: 2 | |
| Dec 24, 2019 at 3:41 | comment | added | Hegedus.Cs | Okay, could you put together that two comment, so I can accept it as answer. Thank you! | |
| Dec 24, 2019 at 3:38 | comment | added | DKNguyen | Honestly, it's difficult to say. But if multiple readings that should read the same are close together you have higher confidence. Filtering is a thing. Getting a 24 bit ADC to actually work at its full potential is an art. | |
| Dec 24, 2019 at 3:35 | comment | added | Hegedus.Cs | So basically I can only be certain with measurements with different loads? | |
| Dec 24, 2019 at 3:27 | comment | added | DKNguyen | Or noise, whichever is higher. | |
| Dec 24, 2019 at 3:25 | comment | added | Hegedus.Cs | Is this also true if I want to measure small voltages, like 0,05 mV or below? It might lead to another question but is hx711 capable of measuring such low signals? According to your formula the answer is yes. | |
| Dec 24, 2019 at 3:23 | comment | added | DKNguyen | Full scale voltage range divided by 2^number of bits | |
| Dec 24, 2019 at 3:19 | history | asked | Hegedus.Cs | CC BY-SA 4.0 |