Timeline for Why do NPN/PNP transistors need to use doped semiconductors for the 'N' region?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 8, 2020 at 5:38 | history | edited | Geza Kerecsenyi | CC BY-SA 4.0 |
added 95 characters in body; edited title
|
| Feb 7, 2020 at 19:43 | answer | added | edmz | timeline score: 0 | |
| Feb 7, 2020 at 18:57 | comment | added | edmz | Generally the terminology 'N/P layers' is not used, because it doesn't make much sense - they are instead referred to as 'N/P regions'. | |
| Feb 7, 2020 at 16:03 | answer | added | analogsystemsrf | timeline score: 1 | |
| Feb 7, 2020 at 9:50 | history | edited | Geza Kerecsenyi | CC BY-SA 4.0 |
added 199 characters in body
|
| Feb 7, 2020 at 9:32 | comment | added | jonk | Study up on Schottky diodes, to start, with a focus on the Fermi levels involved. I've not considered the idea of using a conductor either as the base or as both collector and emitter. But I think it won't work as a transistor because of the Fermi levels. Note that the interface may either be one-way or Ohmic. So I think this is th key here. Perhaps someone specializing in this area will comment. | |
| Feb 7, 2020 at 9:26 | history | edited | Geza Kerecsenyi | CC BY-SA 4.0 |
added 273 characters in body
|
| Feb 7, 2020 at 9:10 | review | First posts | |||
| Feb 7, 2020 at 10:41 | |||||
| Feb 7, 2020 at 9:09 | history | asked | Geza Kerecsenyi | CC BY-SA 4.0 |