Timeline for Physics behind signal reflections and series termination
Current License: CC BY-SA 4.0
21 events
when toggle format | what | by | license | comment | |
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Mar 4, 2020 at 11:24 | vote | accept | Vignesh C | ||
Mar 4, 2020 at 11:24 | vote | accept | Vignesh C | ||
Mar 4, 2020 at 11:24 | |||||
Mar 4, 2020 at 11:22 | vote | accept | Vignesh C | ||
Mar 4, 2020 at 11:24 | |||||
Mar 4, 2020 at 11:22 | vote | accept | Vignesh C | ||
Mar 4, 2020 at 11:22 | |||||
Mar 4, 2020 at 9:35 | comment | added | AndreKR | I found this explanation very good: youtube.com/watch?v=Il_eju4D_TM | |
Mar 4, 2020 at 9:30 | comment | added | jusaca | Very good mechanical visualisation: youtube.com/watch?v=DovunOxlY1k | |
Mar 4, 2020 at 6:21 | comment | added | sweber | Maybe, this helps to understand: electronics.stackexchange.com/questions/171557/… | |
Mar 3, 2020 at 21:00 | history | tweeted | twitter.com/StackElectronix/status/1234946852606423046 | ||
Mar 3, 2020 at 20:10 | comment | added | mbrig | At least in my opinion, it is somewhat easier to start with the physics of 1d vibrational waves in a material that provides a restoring force (say, a taut string), and first understand how reflections (and standing waves) occur there, and then proceed by analogy to EM. | |
Mar 3, 2020 at 19:03 | history | became hot network question | |||
Mar 3, 2020 at 18:42 | comment | added | user57037 | You can study maxwell's equations for the lowest level understanding possible today. Another concept is that an open circuit at the end of a line enforces a certain rule (current = 0) and a short circuit enforces a different rule (voltage = 0). But when you apply a signal to a a transmission line, the signal does not know what is at the end. So power is delivered to the transmission line and energy travels down the line. Only when it gets to the end of the line does the energy learn whether it will be accepted or rejected. | |
Mar 3, 2020 at 18:00 | history | edited | JYelton | CC BY-SA 4.0 |
Capitalization; no space before sentence punctuation in English
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Mar 3, 2020 at 16:29 | answer | added | hotpaw2 | timeline score: 29 | |
Mar 3, 2020 at 16:06 | answer | added | analogsystemsrf | timeline score: 4 | |
Mar 3, 2020 at 15:59 | answer | added | Curd | timeline score: 2 | |
Mar 3, 2020 at 15:08 | answer | added | TimWescott | timeline score: 2 | |
Mar 3, 2020 at 14:38 | comment | added | DKNguyen | Do you understand the analogy of injecting water into a pipe that changes diameter somewhere along its length? The resistor helps dampen reflections from reaching the transmitter and keeps the segment between transmitter and nearest discontinuity really short so reflections that do reach the transmitter die out quickly. It doesn't actually have to be related to the characteristic impedance, but it helps. If you do try to match the resistance you are basically adjusting the driver impedance to match the line. | |
Mar 3, 2020 at 14:31 | comment | added | DKNguyen | You can play with this: helloworld922.blogspot.com/2013/04/… | |
Mar 3, 2020 at 11:32 | history | edited | Vignesh C | CC BY-SA 4.0 |
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Mar 3, 2020 at 11:14 | answer | added | Neil_UK | timeline score: 22 | |
Mar 3, 2020 at 10:58 | history | asked | Vignesh C | CC BY-SA 4.0 |