Timeline for How can I make a 16x16 led pannel without losing the brightness intensity of each single led?
Current License: CC BY-SA 4.0
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Mar 26, 2020 at 17:59 | comment | added | user1850479 | Putting all of the LEDs in series will give the most consistent brightness. If the LEDs are all the same model and from the same batch, putting two parallel strings of 25 each will still be very consistent because variation will average out across the 25 diodes resulting in very close to 700mA per string. Do not put different models of LED in parallel unless you want a fire. You need to pick drivers with both enough power and enough voltage for the strings you're connecting to them. | |
Mar 26, 2020 at 16:52 | vote | accept | Lucas Sievers | ||
Mar 26, 2020 at 14:16 | comment | added | Lucas Sievers | I forgot to say that the foward voltage of the LEDs are 6-7v, to know the voltage that I will need, I must just sum the foward voltage of each led that are in serie (25*7V = 175 V), or just use W/I = V ? are those two options the same ? I hope that I'm not abusing of your good will, I swear that's the last question, will I need then to use 5 LEDs drivers (like this one that you did mention), 1 for each 2x 25 series (if I want to lower the voltage in a half) ? | |
Mar 26, 2020 at 14:16 | comment | added | Lucas Sievers | Thanks for your answer, you were very clear and I think that you solved my problems, but I want to confirm if I really have understand, just to be sure: If I use 2x the current, and then put 2 series of 25 LEDs in parallel, then I can cut the voltage in a half. I can do that because if the two 25 LEDs series are the same then the current will be equally divided and I will have 700 mA for each, its that right ? | |
Mar 26, 2020 at 4:16 | history | answered | user1850479 | CC BY-SA 4.0 |